Chemistry, asked by ankita5552, 9 months ago

Calculate the wavelength, frequency and wavenumber of a light wave whose period is 3.0 x 10⁻¹⁰ s.

Answers

Answered by zahaansajid
1

Time period = T =

3 \times  {10}^{ - 10} s

Frequency = f = 1/T =

 \frac{1}{3 \times 10 {}^{ - 10} }  = 0.33 \times  {10}^{10 }   \\ = 3.33 \times  {10}^{9}  hz

Wavelength = c/f = cT

where, c is the speed of light

T is the time period

=

(3 \times  {10}^{8} ) \times (3 \times  {10}^{ - 10} ) \\  = 9 \times  {10}^{ - 2} m \\  = 9cm

Wave number = 1/Wavelength

=

 \frac{1}{9 \times  {10}^{ - 2} }  = 0.11 \times  {10}^{2}  = 11 {m}^{ - 1}

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