Chemistry, asked by hardeepbuttar35, 1 month ago

calculate the wavelength, frequency, and wavenumber of a light wave whose period is 2×10^-10 s. class11​

Answers

Answered by NewGeneEinstein
2

Answer:-

  • Period of light=2×10^{-10}s
  • Frequency=v=?
  • Wavelength=\lambda=?
  • Wavenumber=\sf \overline{v}

We know that

\boxed{\sf Frequency_{(\nu)}=\dfrac{1}{Period}}

\\ \rm\longmapsto \nu=\dfrac{1}{2\times 10^{-10}}

\\ \rm\longmapsto \nu=5\times 10^9/s

\\ \underline{\boxed{\bf{\therefore \nu=5\times 10^9/s.}}}

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We know that

\boxed{\sf Wavelength_{(\lambda)}=\dfrac{C}{V}}

\\ \rm\longmapsto \lambda=\dfrac{3\times 10^8m/s}{5\times 10^9/s}

\\ \rm\longmapsto \lambda=6\times 10^{-2}m

\\ \underline{\boxed{\bf{\therefore \lambda=6\times 10^{-2}m.}}}

____________________________________

We know that

\boxed{\sf Wavenumber_{(\overline{\nu})}=\dfrac{1}{\lambda}}

\\ \rm\longmapsto \overline{\nu}=\dfrac{1}{6\times 10^{-2}m}

\\ \rm\longmapsto \overline{\nu}=16.6/m

\\ \underline{\boxed{\bf{\therefore \overline{\nu}=16.6/m.}}}

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