Question

calculate the wavelength (in nm) of hydrogen atom(1.67×10^-27) moving at 698cm/s.​

Answer 1

Answer:

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The De Broglie wavelength is the wavelength where particles start to enter the quantum regime and exhibit wave-like properties. The fundamental limit where this happens is given by:

λ

=

h

p

=

h

m

v

where:

p

=

m

v

is the momentum of the particle

h

=

6.626

×

10

−

34

m

2

k

g

/

s

is Planck's constant

Answer 2

Answer:

The De Broglie wavelength is the wavelength where particles start to enter the quantum regime and exhibit wave-like properties. The fundamental limit where this happens is given by:

λ

=

h

p

=

h

m

v

where:

p

=

m

v

is the momentum of the particle

h

=

6.626

×

10

−

34

m

2

k

g

/

s

is Planck's constant

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Explanation:

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