Question

Calculate the wavelength of a particle having momentum $12\times 10^{3} Kgm/s$. Don't spam here........

Answer 1

Answer:

Heya Mate !!! See the above attachment !!! ⬆️

Answer 2

To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength.

$\boxed{\displaystyle\sf{\lambda=\frac{h}{P}}}$

Here,

• $\displaystyle\sf{\lambda=Wave\:Length=x$

• $\displaystyle\sf{h=Planck's\:Constant=6.6\times10^{34}J\:s$

• $\displaystyle\sf{P=\:Momentum\:of\:the\:Particle=12\times10^3\:Kg\:m\:s^{-1}$

Applying the values to the equation,

$\displaystyle\sf{\lambda=\frac{6.6\times10^{-34}}{12\times10^3}$

$\implies\displaystyle\sf{\lambda=0.55\times10^{-34}\times10^{-3}$

$\implies\displaystyle\sf{\lambda=0.55\times10^{-37}$

$\implies\displaystyle\sf{\lambda=5.5\times10^{-38}\:m$

$\boxed{\displaystyle\sf{Wave\:Length(\lambda)=5.5\times10^{-38}\:m}}$