Calculate the wavelength of a photon having an energy of 2 electron volt?
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5
E=h*new
new=c/lembda
now. lembda=(h*c)/E this will help you
new=c/lembda
now. lembda=(h*c)/E this will help you
Answered by
1
Answer:
Explanation:
Energy of one Photon,e=hc/lambda
We have to find the value of lamba:
So,
Lambda=hc/e
=6.625×10^-34×3×10^8/2×1.6×10^-19
=6.204×10-7 m
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