Question

calculate the wavelength of a photon of wavelength 7.62 Armstrong ​

Answer 1

Answer:

1220A

Step-by-step explanation:

E

2

- E

1

= -2.17 × 10

−11

[

4

1

-

1

1

] erg [ n

1

= 1, n

2

= 2]

=2.17 × 10

−11

×

4

3

erg

E

2

- E

1

= hv =

λ

c

h

λ =

ΔE

hc

=

2.17×10

−11

×3/4

6.62×10

−27

erg×3.0×10

10

cm

=

2.17

2.648

10

−5

cm

= 1.22 × 10

−5

cm = 1220A

0

Answer 2

Correct Question:-

Calculate the frequency of a photon of wavelength 7.62Å

Solution

We know

$\boxed{\sf \lambda=\dfrac{C}{V}}$

$\\ \sf\longmapsto v=\dfrac{c}{\lambda}$

$\\ \sf\longmapsto v=\dfrac{3\times 10^8ms^{-1}}{7.62\times 10^{-10}m}$

$\\ \sf\longmapsto v=0.393\times 10^{18}s^{-1}$

$\\ \sf\longmapsto v=3.9\times 10^{17}Hz$