Question

Calculate the wavelength of an electron moving with a velocity of 2.05 x 10^7 m s^-1.​

Answer 1

Answer:

V = 2.05×10⁷ms⁻¹

According to de brogile's equation,

λ = h/mv

where λ is the wavelength (v) of a moving particle

mass(m) = (9.10939× 10 ³¹ g )

h ( plank's constant ) = 6.62 × 10⁻³⁴ J.S

λ = 6.62 × 10⁻³⁴ J.S/ (9.10939× 10 ³¹ g )×(2.05×10⁷ms⁻¹)

= 3.548× 10 ⁻¹¹ m

Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.