Calculate the wavelength of an electron moving with a velocity of 2.05 x 10⁷ m s⁻¹.
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The de Broglie wavelength of anelectron travelling with 10% of velocity of light is equal to a) Chemistry Structure of Atom - 10366121.
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V= 2.05 x107 According to de Broglie's condition,
Where,
λ = wavelength of moving molecule
m = mass of molecule (9.10939 x 10-31)
v = speed of molecule h = Planck's steady (6.62 x 10-34)
Substituting the qualities in the declaration of λ:
Hence, the wavelength of the electron moving with a speed of 2.05 × 107 ms– 1 is 3.548 × 10– 11 m.
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