Calculate the wavelength of an electron that has been accelerated in a particle accelerator through a potential difference of 100 million volts.
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Hii There,
◆ Answer -
λ = 1.225×10^-13 m
● Explaination -
# Given -
V = 100 million = 100 × 10^6 = 10^8 V
# Solution -
Wavelength of electron is calculated by -
λ = h / √(2meV)
Substituting the values, we have a direct formula -
λ = 1.225×10^-9 / √V
λ = 1.225×10^-9 / √(10^8)
λ = 1.225×10^-9 / 10^4
λ = 1.225×10^-13 m
Therefore, wavelength of the electron from particle accelerator is 1.225×10^-13 m.
Thanks dear...
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