Physics, asked by ayazkhanyousafz8585, 3 months ago

Calculate the wavelength of emissionfrom a semiconductor laser whosebandgap energy is 1.8 eV.

Answers

Answered by profdambaldor

0

Answer:

λ = 688.89 nm

Explanation:

E = hc/λ = 1240 eV-nm/λ

1.8 eV= 1240 eV-nm/λ

λ = 688.89 nm

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