Question

Calculate the wavelength of emitted radiation from GaAs which has band gap of 1.44ev

Answer 1

Answer: 861 nm

Explanation:

Energy gap of semiconductor is given by:

$E_g=\frac{hc}{\lambda}$

where, h is the Planck's constant, c is the speed of light, and $\lambda$  is the wavelength of radiation.

We are given that, $E_g=1.44 eV$

$1 eV=1.602\times 10^{-19} J$

$\Rightarrow 1.44 eV = 2.31 \times 10^{-19} J$

$c=3.0\times 10^8 m/s$

[tex]h = 6.63 \times 10^{-34} m^2 kg/s [/tex]

Substitute the values to find the wavelength of radiation:

$\Rightarrow \lambda = \frac{hc}{E_g}=\frac{6.63 \times 10^{-34} m^2 kg/s \times 3.0\times 10^8 m/s}{2.31 \times 10^{-19} J}=8.61 \times 10^ -7 m =861 nm$

Hence, the wavelength of the emitted radiation from GaAs which has band gap of 1.44 eV is 861 nm.

Answer 2

Answer:

a) 8628 A°

b) 8682 A°

c) 8632 A°

d) 8685 A°