Calculate the wavelength of light required to break the bond between two chlorine atoms
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we know that the cl-cl energy is 243kjmol-1.
by the formula lambda=hc/E
lambda=(6.625*10^-34)*(3*10^8)/4*10^-19
= 19. 875*10^-7/4=488nm
by the formula lambda=hc/E
lambda=(6.625*10^-34)*(3*10^8)/4*10^-19
= 19. 875*10^-7/4=488nm
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