Question

calculate the wavelength of limiting line of lyman series​

Answer 1

The wavelength of limiting line of Lyman series is 911

A

˚

. The atomic number of the element which emits minimum wavelength of 0.7

A

˚

of X-rays will be

E=

λ

hc

=kZ

2

(

n

1

2

1

−

n

2

2

1

)

For Lyman, n

1

=1 and limiting line means the electron is ejected from orbit n

2

= infinity

λ

1

=kZ

2

(

n

1

2

1

−

n

2

2

1

For case 2, same conditions except different atomic number.

λ

2

λ

1

=Z

2

0.7

911

=Z

2

Z=37

i hope it helps you