Calculate the wavelength of moving object 'X' so that its momentum is four times that of the moving object 'Z' having wavelength 2.6×10^-10m.
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Explanation:
V= 2.05 x107 (given)
By de Broglie’s equation,
λ = wavelength of moving particle
m = mass of particle (9.10939 x 10-31)
v = velocity of particle
h = Planck’s constant (6.62 x 10-34)
Substituting the values in the expression of λ:
in the file.............
Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.
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