Question

Calculate the wavelength of proton which is accelerated by a potential of 35 volts ( mass of proton = 1.66 multiplied by 10^-27 kg )

Answer 1

eV=KE=

2

1

mv

2

KE=

2m

p

2

De-broglie wavelength,

λ=

p

h

λ=

2mE

h

=

2mVe

h

Putting the values of constants, we get:

λ=

2×1.6×10

−27

×1.6×10

−19

×1000

6.6×10

−34

=0.9×10

−12

m