Question

Calculate the wavelength of radiation which excites the electron og hydrogen atom from ground state to fourth energy. Ionization energy of hydrogen atom is 1312

Answer 1

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Answer 2

Explanation:

Answer

Correct option is

C

−6.8 eV

Total energy of Hydrogen atom in ground state is −13.6eV ,and potential energy is −27.2ev, Kinetic energy =13.6eV

For first excited state Kinetic energy = 3.4eV, Potential energy= −6.8eV,

If potential energy of first excited energy is zero , Then for this we must add 6.8eV energy in system . We are just shifting the potential refrence.

So for ground state total energy =(13.6−27.2+6.8)=−6.8eV