Calculate the wavelength of radiations emitted producing a line in Lyman series,when an electron falls from fourth stationary state in hydrogen atom (RH=1.1×107m−1)
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U cn use the formula of hydrogen spectrum in this to solve it
U cn use the formula of hydrogen spectrum in this to solve it
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Answer:
λ=0.9696×10−7m)
Explanation:
1λ=RH[1n21−1n22]
Given RH = 1.1×107 for Lyman series n1=1and n2=4 (gives )
Therefore ,
1λ=1.1×107[112−142]
λ=0.9696×10−7m
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