Question

calculate the wavelength of s radiation emitted when the 6th orbit forms a balmer series​

Answer 1

Answer:

Calculate the wavelength of radiation emitted when electron in a hydrogen atom jumps from n=°° to n=1.

Explanation:

Hope this answer will help you dear...

Answer 2

Answer:

The energy of n

th

level for any atom is determined by the radius and quantum number by:

E

n

=−

2ℏ

2

n

2

Z

2

k

e

2

e

4

m

e

For hydrogen atom the energy varies with shell number as:

E

n

=−13.6

n

2

1

eV

Energy energy released from jump of electron from n=∞ to n=1 is:

E=−13.6(

∞

1

−(

1

2

1

))eV

=13.6eV

Photon of this energy is given by, E=

λ

hc

⟹λ=

E

hc

=91.17nm