Calculate the wavelength of second line of Lyman series in hydrogen spectra
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Answered by
4
lymanseries second line means electron jumps from 3level to second level
n1=1,n2=3
R is constnt=1.08×10power7
1/wavelength=1.08×10power7 [1|n1square_1/n2square]
wavelength=10.4×10powerminus8 metres
n1=1,n2=3
R is constnt=1.08×10power7
1/wavelength=1.08×10power7 [1|n1square_1/n2square]
wavelength=10.4×10powerminus8 metres
Answered by
7
1/ λ = R[1/n₁² - 1/n₂²]
For second line of Lyman series
n₁ = 1 and n₂ = 3
1/λ = R[1/1² - 1/3²]
= 8R/9
λ = 9 / (8R)
= 9 / (8 × 1.097 × 10^7 m^1)
= 102.5 nm
∴ Wavelength of second line of Lyman series is 102.5 nm
For second line of Lyman series
n₁ = 1 and n₂ = 3
1/λ = R[1/1² - 1/3²]
= 8R/9
λ = 9 / (8R)
= 9 / (8 × 1.097 × 10^7 m^1)
= 102.5 nm
∴ Wavelength of second line of Lyman series is 102.5 nm
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