calculate the wavelength of spectral line in Lyman series when as electron falls from third energy level in hydrogen atom
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Answer:
9.69×10
−8
metres
∴
λ
1
=R
H
[
n
1
2
1
−
n
2
2
1
]
Given; R
H
=1.1×10
7
; for Lyman series n
1
=1 and n
2
=4(given)
∴
λ
1
=1.1×10
7
[
1
2
1
−
4
2
1
]
∴9.69×10
−8
metre
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