Question

) Calculate the wavelength of the first line of Balmer
series in hydrogen spectra. (Given Rh =1.09737 cm)​

Answer 1

PLEASE Mark it BRAINLIEST

Answer 2

Answer:

n 1 = 2

n2 = 3

1/lemda = RZ2 (1/n1^2 - 1//n2^2)

Lemda = 36/5R

lemda = 6.56 × 10^-7

Thanks for Reading