Question

Calculate the wavelength of the radiation emitted when an electron in a hydrogen atom makes a transition from an energy level with n=4 to n=1

Answer 1

Answer:

Explanation:

According to Balmer formula

Wave no = RH [1/n1^2 – 1/n2^2]

Here n1 = 1 , n2 = 4, RH = 109678

Putting these values in the equation we get

Wave number =109678(1/1^2 - 1/4^2) = 109678 x 15/16

Also λ = 1/ wave number

Therefore λ = 16 / 109678 x 15 = 102823.125 nm

Answer 2

Explanation:

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