Calculate the wavenumber for the longest and shortest wavelength transition in the paschen series of atomic hydrogen
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Answer: Here are the answers!!!
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Explanation:
transition should be from orbit 3 to 2
1/A = R ×1^2 ((1/2^2)-(1/3^2))
A is wavelength
R is rhydberg constant ( you can use 1/R =912 Angstrom)
it will make calculation convenient
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