Question

Calculate the wavenumber for the longest and shortest wavelength transition in the paschen series of atomic hydrogen​

Answer 1

Answer: Here are the answers!!!

Explanation:

Answer 2

Answer:

Explanation:

transition should be from orbit 3 to 2

1/A = R ×1^2 ((1/2^2)-(1/3^2))

A is wavelength

R is rhydberg constant ( you can use 1/R =912 Angstrom)

it will make calculation convenient