Question

Calculate the weight and volume of air required for combustion of 3 kg of carbon

Answer 1

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How do I calculate the volume of air required for complete combustion of a ... 1 kg of carbon requires (8/3 ) kg of oxygen.

Answer 2

The weight and volume of air required for the combustion of 3 kg of carbon are 8kg and 5.602 x 10³ L respectively.

​Given:

3 kg of carbon undergoes combustion.

To Find:

The weight and volume of air required for the combustion.

Solution:

The chemical reaction for the combustion of carbon is given below:

$C_{(s)}$ + $O_{2} _{(g)}$ = $CO_{2} _{(g)}$ + Δ

i.e. the combustion of carbon in the air gives carbon-di-oxide and heat.

We need to calculate the weight and volume of  $O_{2} _{(g)}$ here.

Here, the mass of $C_{(s)}$ is 12g, and that of $O_{2} _{(g)}$ is 16 x 2 = 32g.

⇒ 12g of carbon requires 32g of oxygen.

So the amount of oxygen 3000g (= 3kg) of carbon will require is

= 32/12 x 3000  = 8/3 x 3000 = 8000g = 8 kg.

Hence the amount of oxygen (it's mass ) required is 8kg.

We know that,

Density = Mass/Volume

We know that the density of  $O_{2} _{(g)}$  at NTP = 1.428gm/L

Hence,

The volume of air required for combustion of 3 kg of carbon = Mass/Volume = 8000/ 1.428 = 5.602 x 10³ L.

∴ The weight and volume of air required for the combustion of 3 kg of carbon are 8kg and 5.602 x 10³ L respectively.

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