Calculate the weight in grams of 24.088x10^23 molecules of H20
Answers
we have to calculate the weight in grams of 24.088 × 10²³ molecules of H₂O.
solution : first we should find the no of moles of water molecules.
no of moles of water molecules = no of molecules/avogadro's no
= 24.088 × 10²³/6.022 × 10²³ = 4 mol
we also know, no of moles of any substance = given weight/molecular weight of the substance.
molecular weight of water = 18 g/mol
no of moles of water = 4 mol
∴ given weight = no of moles of water × molecular weight of water
= 4 mol × 18 g/mol = 72 g
therefore the weight of water is 72 g.
Answer:
72 g
Explanation:
number of moles of water = no. of molecules
avogadro's no.
= 24.088 × 10²³
6.022 × 10²³
= 4 mol
molecular mass of H2O = 1×2+16 =18 g/mol
given mass = no. of moles × molecular weight
= 4×18 = 72g