Question

calculate the weight in grams of 5.8× 10²⁴ molecule of butane c⁴ h¹⁰​

Answer 1

Mass of C4H10= (12×4)+10

= 58 gm

Weight of 6.022×10²³ molecules = 58 gm

Weight of 1 molecule = 58/(6.022×10²³) gm

Weight of 5.8×10²⁴ molecules =

$\frac{58 \times 5.8 \times {10}^{24} }{6.022 \times {10}^{23} }$

= 558.618 gm