Chemistry, asked by akulasubbarao88, 6 months ago

calculate the weight of 0.25mole at NH4CL

Answers

Answered by hitengosain15

0

Answer:

Applying the equation

pOH=log

[Base]

[Salt]

−logK

b

=log

0.15

0.25

−log1.8×10

−5

=4.966

pH=(14−4.966)=9.034

Explanation:

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