calculate the weight of 0.5moles of sulphurous acid
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Answered by
10
Sulphurous acid
Formula :-
H2SO3
Hence it's molar mass =
(1 × 2)+ 32 + (16 × 3)
= 2 + 32 + 48
= 82 molar mass
Given mole = 0.5 and
Molar mass = 82
We know that, mole = weight (in grams)/ molar mass
Hence,
0.5 = (weight in grams)/82
=> weight = 82 × 0.5
=> weight = 41 grams
Hope it helps dear friend ☺️✌️✌️
Formula :-
H2SO3
Hence it's molar mass =
(1 × 2)+ 32 + (16 × 3)
= 2 + 32 + 48
= 82 molar mass
Given mole = 0.5 and
Molar mass = 82
We know that, mole = weight (in grams)/ molar mass
Hence,
0.5 = (weight in grams)/82
=> weight = 82 × 0.5
=> weight = 41 grams
Hope it helps dear friend ☺️✌️✌️
Mankuthemonkey01:
@vishal oops i thought it was sulphuric (^^)"" lemme edit if i get the option
done
ok
Mayankkushwaha are you there? i need a help from you.
Hmm yes?
actually i did a mistake in one of my answer i realised lately so i called you to report my answer so that i can get an edit option. .because i cannot report my own answer. .luckily the moderator responded i corrected the answer. .thank you for responding for my message.
so the problem is solved?
well i am also a mod
yes the problem has been solved. . . .oh! iam not aware that you are also a mod. .thank you for letting me know that. .further if something comes. .i will have a word with you.
✌️
Answered by
5
we know that one mole of sulphurous acid (H₂SO₃) weighs = (2 + 32 + 48) = 82 grams.
0.5 moles of sulphurous acid weighs 82/2 grams = 41 grams
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