Question

calculate the weight of 5.6litres of NH3 at S.T.P​

Answer 1

Answer:

First and foremost, keeping in mind that at room temperature, Oxygen is a gas.

So, Volume of Oxygen(O2) given = 5.6L.

Finding moles, Moles=Volume/22.4.

Moles= 5.6/22.4=1/4moles.

So, finding mass of O2= moles × Mol. Wt.

Mass( in grams) = 1/4 × 32. We have taken 32 as oxygen is is combined state O2, so 16×2=32.

We get, mass =8 grams. This is mass not active mass.

Active mass means molarity which will be

0.25/5.6= 0.044