Question

calculate the weight of 6.022 × 10 ^23 molecules of calcium carbonate

Answer 1

6.022×10²³ molecules represent 1 mole of substance which is equal to the molecular weight of the given substance. Here, the substance is calcium carbonate i.e., CaCO3 whose molecular mass is= 40 + 12 + (3×16) = 100 g

Answer 2

Hello user☺☺


6.022 × 10 ^23 molecules of calcium carbonate = 1 mole of CaCO3

Mass of 1 mole = 100g