Question

Calculate the weight of 6.022 into 10 to the power 23 molecules of caco3

Answer 1

Answer:

100

Explanation:

Given weight=?

Molecular weight of CaCO3=40+12+3(16)

=40+12+48

=100g

Given moles of CaCO3=6.022×10²³

So,

No. Of moles of CaCO3= (no. Of molecule of CaCO3)/NA

No. Of moles of CaCO3=6.022×10²³/6.022×10²³

No. Of moles of CaCO3=1

Now,

No. Of moles of CaCO3=

(given weight of CaCO3)/(molecular weight of CaCO3)

No. Of moles of CaCO3= (given weight of CaCO3)/100

1 =(given weight of CaCO3)/100

☆☆100g= weight of CaCO3 ☆☆

Hope it would.d be helpful!!!!!!!!

Answer 2

$\huge\red{\boxed{\bold{Solutions}}}$

• No. Of moles of CaCO3 = no. Of molecules/Ab. Cons

$\implies$ 6.022 × 10^23 / 6.022 × 10^23

$\implies$ 1

• Weight of CaCO3 = no. Of moles × molecules at.

$\implies$ 1 × 100 = 100 g.

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