Physics, asked by aneesshreen5595, 4 months ago

Calculate the weight of 60% of sulphuric acid to decompose 50g of calcium carbonate

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Answered by aashuyadavtilakdhari

0

Answer:

MM of CaCO3 is 40 + 12 + 48 = 100Equation CaCO3 + H2SO4 = CaSO4 + CO2 + H2OSo 1 mole of calcium carbonate reacts with 1 mole of sulphuric acid.In the question 50 g of CaCO3 used which is 0.5 moles. H2SO4 is 2 + 32 + 64 = 98 0.5 moles is 49 g of H2SO4This is a 60% solution so the answer is 100 x 49 / 60 = 81.67

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