Question

Calculate the weight of 90% of cap that can be prepared by heating 200kg of caco3 which is 90%, pure??

Answer 1

Mass of  CaCO₃ in 200 grams of 90% pure calcium carbonate is 180 grams
no. of moles of CaCO₃ in 180 grams of CaCO₃ is 180/100=1.8 moles

so, 1.8 moles each of CaO and CO₂ are formed by Decomposition of 1.8 moles of CaCO₃.

CaCO₃------------Δ------------->>> CaO + CO₂

mass of 1 mole CaO is 56 grams
mass of 1.8 moles of CaO is 56*1.8=100.8 grams

Answer 2

mass of  CaCO₃ in 200 grams of 90% pure calcium carbonate is 180 grams

no. of moles of CaCO₃ in 180 grams of CaCO₃ is 180/100=1.8 moles

so, 1.8 moles each of CaO and CO₂ are formed by Decomposition of 1.8 moles of CaCO₃.

CaCO₃------------Δ------------->>> CaO + CO₂

mass of 1 mole CaO is 56 grams

mass of 1.8 moles of CaO is 56*1.8=100.8 grams