Question

Calculate the weight of ammonia gas required for reacting with sulphuric acid to give 78g of fertilizer ammonium sulphate. (N=14; H=1; S=32; O=16)

Answer 1

Answer: 20,4 g

Explanation:

The equation: 2NH3+H2SO4 ---> (NH4)2SO4

Molar mass of ammonium sulphate: ((14+4) x 2) + 32 + (16x 4) = 36 + 32 +64 = 132 g

78 g of ammonium sulphate = 78/132 mol = 0.6 mol

2 mol of ammonia gas (NH3) is required to produce 1 mol of ammonium sulphate

1.2 mol of NH3 is required to produce 0.6 mol of ammonium sulphate

1.2 mol of NH3 has a mass of 1.2 x (14 + 3) = 20.4 g