Calculate the weight of C6H12O6 (glucose) which contains 64gm of oxygen. (Please keep the explanation as simple as possible im in class 11 trying to understand mole)
Answers
Answer:The mass of one mole of the substance is said to be the molar mass of that substance. It is usually expressed in g/mol but its SI base unit is kg/mol. It is not a molecular property of a substance but its bulk property.
A mole of any substance has exactly 6.022×1023 particles which can be ions, atoms, electrons, or molecules.
Now, the molecular mass of one mole of a compound can be calculated by taking the sum of atomic masses of all the elements present in the molecule.
It is given to us that the atomic masses of elements present in glucose are
C = 12 u
H = 1 u
O = 16 u
Since the molecular formula of glucose is C6H12O6, it has 6 atoms of carbon element, 12 atoms of hydrogen element, and 6 atoms of oxygen element
So, its molecular mass will be
MC6H12O6=6×MC+12×MH+6×MOMC6H12O6=6×12+12×1+6×16MC6H12O6=180g/mol
Hence the molecular mass of glucose having molecular formula C6H12O6 is 180 g/mol.
Explanation:
Answer:
120 gm
Explanation:
Molecular mass of C6H12O6 is 180gm
- Mole of O atoms = 64/16 = 4 moles
- 6 atoms of O are present in one molecule of C6H12O6 .... So 4 moles of O atom 4/6*180 = 120 gm