Question

Calculate the weight of Carbon dioxide formed by complete combustion of 1.5 g of ethane using Principle of atomic conservation.​

Answer 1

Molar mass of ethane ( C2H6) = 12×2+6×1= 30g

No. of moles 1.5g of ethane= 1.5g/30g = 0.05 moles.

Now the balanced reaction of combustion of ethane is 2(C2H6) + 7(O2) = 6(H2O) + 4(CO2)

By equation, 2 moles of C2H6 will give 4 moles of CO2 .

So 1 mole of C2H6 will give 2 moles of CO2.

So 0.05 moles of C2H6 will give (0.05×2) moles of CO2 = 0.1 moles of CO2.

Molar mass of CO2 = 12+16×2=44g

Mass of 0.1 mole of CO2= 44g × 0.1 = 4.4g

So answer is 4.4g of CO2 will be formed.

Principle of atomic conservation is followed here by using the balanced chemical equation.

Answer 2

Answer:

The weight of Carbon dioxide is 4.4g of CO2 will be formed.

Explanation:

The principle of atomic conservation is followed here by using the balanced chemical equation.

Elements combine in the whole number, that we know to be true. Thus, we need to have the smallest wwhole number ratio of the coefficients used to balance the equation. To balance an equation initially, you may use a fraction, but then you must modify the coefficients to make them whole numbers. Below is an example.

Molar mass of ethane ( C2H6) = 12×2+6×1= 30g

No. of moles 1.5g of ethane= 1.5g/30g = 0.05 moles.

Now the balanced reaction of combustion of ethane is 2(C2H6) + 7(O2) = 6(H2O) + 4(CO2)

By equation, 2 moles of C2H6 will give 4 moles of CO2.

So 1 mole of C2H6 will give 2 moles of CO2.

So 0.05 moles of C2H6 will give (0.05×2) moles of CO2 = 0.1 moles of CO2.

• Molar mass of CO2 = 12+16×2=44g

• Mass of 0.1 mole of CO2= 44g × 0.1 = 4.4g

Hence, The weight of Carbon dioxide is 4.4g of CO2 will be formed.

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