Question

calculate the weight of carbon monoxide having same number of oxygen atoms as are present in 22g of carbon dioxide ​

Answer 1

Answer:

molecular weight of carbon monoxide=12+16=28

total molecules in 22g of CO2=22/44=

Na/2

in one molecule of carbon dioxide oxygen atom=2

inNa/2 molecules oxygen present=Na/2 ×2=Na

Now for Na molecules of oxygen,carbon monoxide required=Na

so mass of Na molecules of CO=28g

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Answer 2

Answer:

Molar mass CO2 = 44g/mol

22g CO2 = 0.5 mol

1mol CO2 has 2 mol O atoms

0.5 mol CO2 has 1 mol O atoms

1mol CO has 1 mol O atoms

Molar mass CO = 12+16 = 28g/mol

28g CO has same number of O atoms as 22g CO2

Explanation: