Question

Calculate the weight of Carbon Monoxide having the same number of oxygen atoms as are present in 22 g of carbon dioxide.​

Answer 1

Answer:

28g of CO contains 6.023 x 10²³ atoms of O. 6.023 x 1023 molecules = 2 x 6.023 x 1023 atoms of O. So, 44 g = 2 x 6.023 x 1023 atoms of O. 22 g of CO2 = (22 x 2 x 6.023 x 1023)/44 = 6.023 x 1023 atoms of O

Answer 2

22 g of CO2 = (22 x 2 x 6.023 x 1023)/44 = 6.023 x 1023 atoms of O. Now, 1 mole of CO = 6.023 x 1023 atoms of O. Therefore. 28g of CO = 6.023 x 1023 atoms of O.

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