Question

calculate the weight of carbon monoxide having the same no. of O atoms as are present in 22gm of CO2

Answer 1

Molar mass of CO₂ = 44g
& Molar mass of CO = 28g

Now,
44g of CO₂ = 1mole = 6.022 × 10²³ molecules
So, 22g of CO₂ = 3.011 × 10²³ molecules.

In 22g of CO₂ there are 3.011 × 10²³ molecules. And each molecule of CO₂ contains 2 atoms of Oxygen.
So number of Oxygen atoms in 22g of CO₂ = 2×3.011 × 10²³ = 6.022 × 10²³ atoms.

In CO,
Each molecule of CO contains 1 Oxygen atom
So 1mole of CO will contain 1 mole of Oxygen atoms, i.e., 6.022 × 10²³ atoms.

Thus the required mass of CO containing same number of O atoms as present in 22gm of CO₂ is molar mass of CO i.e., 28g of CO.

HOPE IT HELPS...... :-)