Question

calculate the weight of CH4 in a 9 litre cylinder at 16 atm and 27°C
plz answer in numerical​

Answer 1

Answer:

Given, p= 16 atm, v=9L, n=m/M ,where M is molecular weight of Methane i.e, 16, R= 0.0821 T = 27+273=300

Ideal gas equation PV=m/M RT

16x9= m/16 x0.0821x300=96grams

Explanation:

Answer 2

Answer: 93.5 grams

Explanation:

According to the ideal gas equation:'

$PV=nRT$

P = Pressure of the gas = 16 atm

V= Volume of the gas = 9 L

T= Temperature of the gas = 27°C = 300 K (0°C = 273 K)

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= ?

[tex]n=\frac{PV}{RT}=\frac{16atm\times 9L}{0.0821atmL/K mol \times 300K}=5.85moles[/tex]

mass of $CH_4=moles\times {\text {molar mass}}=5.85mol\times 16g/mol=93.5g$

Thus the weight of $CH_4$ in a 9 litre cylinder at 16 atm and 27°C is 93.5 grams.