Chemistry, asked by mokshitamadan, 8 months ago

calculate the weight of co having same no. of o2 atoms as are present in 22 g of co2​

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Answered by vishal20573
1

Answer:

22 g of CO2 = (22 x 2 x 6.023 x 1023)/44 = 6.023 x 1023 atoms of O. Now, 1 mole of CO = 6.023 x 1023 atoms of O. Therefore. 28g of CO = 6.023 x 1023 atoms of O.

Answered by basundhara30
0

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