Physics, asked by mll, 1 year ago

calculate the weight of co having the same number of 02 atoms present in 22g of co2

Answers

Answered by prmkulk1978
617
Molar Mass of CO2=44g

1 mole of CO2 [ 44g ] contains 6.022 x10²³ molecules.

1molecule of CO2=2 atoms of O

6.022 x10 ²³ molecules=2x6.023x10²³ atoms of O

so, 44g            ------> 2x6.023x10²³ atoms of O
    22gg of CO2  ----?

 =22x2x6.023x10²³/44
=6.023x10²³ atoms of Oxygen.

1 mole of CO =6.023 x 10²³atoms of O.
1 mole of CO=28g
∴28g of CO contains 6.023 x 10²³ atoms of O.

Answered by adityaujwall
128

Molar Mass of CO2=44g

1 mole of CO2 [ 44g ] contains 6.022 x10²³ molecules.

1molecule of CO2=2 atoms of O

6.022 x10 ²³ molecules=2x6.023x10²³ atoms of O

so, 44g            ------> 2x6.023x10²³ atoms of O

   22gg of CO2  ----?

 =22x2x6.023x10²³/44

=6.023x10²³ atoms of Oxygen.

1 mole of CO =6.023 x 10²³atoms of O.

1 mole of CO=28g

∴28g of CO contains 6.023 x 10²³ atoms of O.

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