calculate the weight of co having the same number of 02 atoms present in 22g of co2
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Answered by
617
Molar Mass of CO2=44g
1 mole of CO2 [ 44g ] contains 6.022 x10²³ molecules.
1molecule of CO2=2 atoms of O
6.022 x10 ²³ molecules=2x6.023x10²³ atoms of O
so, 44g ------> 2x6.023x10²³ atoms of O
22gg of CO2 ----?
=22x2x6.023x10²³/44
=6.023x10²³ atoms of Oxygen.
1 mole of CO =6.023 x 10²³atoms of O.
1 mole of CO=28g
∴28g of CO contains 6.023 x 10²³ atoms of O.
1 mole of CO2 [ 44g ] contains 6.022 x10²³ molecules.
1molecule of CO2=2 atoms of O
6.022 x10 ²³ molecules=2x6.023x10²³ atoms of O
so, 44g ------> 2x6.023x10²³ atoms of O
22gg of CO2 ----?
=22x2x6.023x10²³/44
=6.023x10²³ atoms of Oxygen.
1 mole of CO =6.023 x 10²³atoms of O.
1 mole of CO=28g
∴28g of CO contains 6.023 x 10²³ atoms of O.
Answered by
128
Molar Mass of CO2=44g
1 mole of CO2 [ 44g ] contains 6.022 x10²³ molecules.
1molecule of CO2=2 atoms of O
6.022 x10 ²³ molecules=2x6.023x10²³ atoms of O
so, 44g ------> 2x6.023x10²³ atoms of O
22gg of CO2 ----?
=22x2x6.023x10²³/44
=6.023x10²³ atoms of Oxygen.
1 mole of CO =6.023 x 10²³atoms of O.
1 mole of CO=28g
∴28g of CO contains 6.023 x 10²³ atoms of O.
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