Question

Calculate the weight of CO having the same number of oxygen atoms as are present in 22g
of CO2
​

Answer 1

↪Mole Concept↩

Molar mass of CO2 molecule = 44g

No. of moles of CO2 in 22g

=》 22/44

=》1/2 mole

No. of Atoms present in 1/2 mole of CO2 = 1/2 × 2

= 1 mole oxygen atoms.

No. of Oxygen atoms in CO2 = No. of Oxygen atoms in CO.

Therefore , weight of CO molecules having 1 mole oxygen atoms

= 12 × 1 + 16 × 1

= 28 g.

Answer 2

The molar mass of CO2 = 44 g/mol

1 mole of CO2 weighs 44g

1 mole of CO2 = 6.023 x 1023 molecules

1 molecule of CO2 = 2 atoms of O

6.023 x 1023 molecules = 2 x 6.023 x 1023 atoms of O.

So, 44 g = 2 x 6.023 x 1023 atoms of O.

22 g of CO2 = (22 x 2 x 6.023 x 1023)/44 = 6.023 x 1023 atoms of O.

Now, 1 mole of CO = 6.023 x 1023 atoms of O.

1 mole of CO = 28 g

Therefore. 28g of CO = 6.023 x 1023 atoms of O.