Question

Calculate the weight of CO having the same number of oxygen atoms as are present in 22 g
of CO2​

Answer 1

Explanation:

Molar Mass of CO2=44g

1 mole of CO2 [ 44g ] contains 6.022 x10²³ molecules.

1molecule of CO2=2 atoms of O

6.022 x10 ²³ molecules=2x6.023x10²³ atoms of O

so, 44g            ------> 2x6.023x10²³ atoms of O

    22gg of CO2  ----?

 =22x2x6.023x10²³/44

=6.023x10²³ atoms of Oxygen.

1 mole of CO =6.023 x 10²³atoms of O.

1 mole of CO=28g

∴28g of CO contains 6.023 x 10²³ atoms of O.

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