Question

Calculate the weight of CO having the same number of oxygen atoms as are present in 22g of CO2?

Answer 1

Calculate the weight of
Molar Mass of CO2=44g

1 mole of CO2 [ 44g ] contains 6.022 x10²³ molecules.

1molecule of CO2=2 atoms of O

6.022 x10 ²³ molecules=2x6.023x10²³ atoms of O

so, 44g ------> 2x6.023x10²³ atoms of O
22gg of CO2 ----?

=22x2x6.023x10²³/44
=6.023x10²³ atoms of Oxygen.

1 mole of CO =6.023 x 10²³atoms of O.
1 mole of CO=28g
∴28g of CO contains 6.023 x 10²³ atoms of O.

Answer 2

The molar mass of CO2 = 44 g/mol

1 mole of CO2 weighs 44g

1 mole of CO2 = 6.023 x 1023 molecules

1 molecule of CO2 = 2 atoms of O

6.023 x 1023 molecules = 2 x 6.023 x 1023 atoms of O.

So, 44 g = 2 x 6.023 x 1023 atoms of O.

22 g of CO2 = (22 x 2 x 6.023 x 1023)/44 = 6.023 x 1023 atoms of O.

Now, 1 mole of CO = 6.023 x 1023 atoms of O.

1 mole of CO = 28 g

Therefore. 28g of CO = 6.023 x 1023 atoms of O.