Calculate the weight of glucose required to prepare 500ml of 0.1 solution?
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Molarity of solution = 0.1 mol/L
Volume of solution = 500ml = 0.5L
Moles of glucose = M × V = 0.1 × 0.5 = 0.05 mol
Weight of glucose = moles × molar mass = 0.05 × 180 = 9g
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