calculate the weight of gold having specific heat capacity 0.13 solve inverse gram University which is heated from 25 degree centigrade to 300 degree centigrade where the heat absorbed is 1500 joules
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The weight of gold having specific heat capacity 0.13 = 41.95 g
Explanation:
Q= m x c x ΔT
Q= heat gained = 1500 J
m= mass of the substance = ?
c = heat capacity of gold= 0.13 J/g °C
ΔT= Change in temperature = (300-25) °C= 275°C
1500 J= m x 0.13 J/g °C x 275 °C
m=41.95 g
Thus the weight of gold having specific heat capacity 0.13 = 41.9 g
Also learn more
A 4.0 kg aluminum block is originally at 10°C. If
160 kJ of heat is added to the block, what is its final
temperature? The specific heat capacity of aluminum
is 910 J/kg · K.
(a) 24°C
(6) 34°C
(c) 44°C
(d) 54°C
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