Question

Calculate the weight of lime ( CaO) obtained by heating 2000 kg of 95% pure lime stone ( CaCO3)

Answer 1

Answer: 1064 kg

Explanation: ${\text{Number of moles}}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of $CaCO_3=2000 kg=2\times 10^6g$

Molar mass of $CaCO_3$ = 100 g/mol

Putting values in above equation, we get:

$\text{Number of moles}=\frac{2\times 10^6g}{100g/mol}=20000moles$

$CaCO_3\rightarrow CaO+CO_2$

By Stoichiometry:

1 mole of $CaCO_3$ produces 1 mole of $CaO$

So, 20000 moles of $CaCO_3$ produce =$\frac{1}{1}\times 20000=20000moles$  of $CaO$

But the conversion is only  95%, thus moles of $CaO=\frac{95}{100}\times 20000=19000moles$

Mass of $CaO={\text {no of moles}}\times {\text {Molar mass}}$

Mass of $CaO=19000\times 56g/mol=1064000g=1064kg$

Answer 2

Answer:

1064kg

Explanation: