Question

calculate the weight of methane required to react with 50g of o2 and calculate the mass of CO2 and H2O produced?

Answer 1

Answer:

weight of methane required = 12.5g

mass of CO2 produced = 34.375g

mass of H2O produced = 28.125g

Explanation:

CH4 + 2O2 -------> CO2 + 2H2O

16g. 64g. 44g. 36g

? 50g. ? ?

now we can find mass of methane by cross multiplication

CH4. 2O2

16g. 64g.

? 50g

$\frac{16 \times 50}{64 } = 12.5g \: (mass \: \: of \: \: methane)$

so mass of me thane is 12.5 g.

Now, we similarly find maza of CO2 and H2O produced

2O2. CO2

64g. 44g

50g. ?

$\frac{50 \times 44}{64} = 34.375 g$

2O2. 2H2O

64g. 36g

50g. ?

$\frac{50 \times 36}{64 } = 28.125g$

HENCE, MASS OF METHANE =12.5 g

MASS OF CO2. =34.375g

MASS OF WATER. =28.125g

thank you !!

PLEASE MARK AS BRAINLIEST