Calculate the weight of N2 in 6.24 litre cylinder at 27∘C and 750 mm Hg. (R = 0.0821 litre atm K−1mol−1)
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Moles of Nitrogen = Weight / Molar mass
= 7 g / (28 g/mol)
= 0.25 mol
Pressure = 750 mm Hg
= (750/760) atm ………[∵ 1 atm = 760 mm Hg]
= 75/76 atm
From ideal gas equation
V = nRT/P
= (0.25 mol × 0.0821 atm.L / (mol K) × 300 K) / (75/76 atm)
= 6.2396 liters
Volume occupied by gas is 6.2396 liters
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